Question

i3+(6+3i)-(20+5i)+(14+3i)
solve
complex number
​

Answer 1

Answer:

i3+( 9i)_ ( 25i)+( 17i)

Step-by-step explanation:

i3+9i_ 25i+17i =12i _25i +17i = 13i+17i=30i ANSWER

Answer 2

Answer:

0

Step-by-step explanation:

i^3+(6+3i)-(20+5i)+(14+3i)

i^3+(6-20)+(3i-5i)+(14+3i)

i^3+(-14)+(-2i)+(14+3i)

i^3+(-14-2i)+(14+3i)

i^3+(-14+14)+(-2i+3i)

i^3+i

-i+i = 0 (we know i^3=-i

Therefore, 0 is the required answer