Question

(i⁶¹³+1/i⁹¹⁴) solve this problem​

Answer 1

Step-by-step explanation:

We have,

${i}^{613} + \dfrac{1}{ {i}^{914} }$

$= {i}^{( 4 \times153 + 1)} + \dfrac{1}{ {i}^{(4 \times 228 + 2)} }$

$= i+ \dfrac{1}{ {i}^{ 2} }$

$= i+ \dfrac{1}{ - 1}$

$= i - 1$