Question

Iabcd is a cyclic quad.If anglebac =50 and angledbc=60 then find angle bcd

Answer 1

Since we know that ABCD is a cyclic quadrilateral.

Therefore, angle BAC + angle BDC = 180°

50° + angle BDC = 180° ( Given )

angle BDC = 180° - 50° = 130°_(1)

Now in triangle BDC,

angle DBC + angle BDC + angle BCD = 180° ( by angle sum property of the triangle )

60° + 130° + angle BCD = 180° [ Given and from eq. ( 1 ) ]

angle BCD = 180° -190°