Question

ICBSE 2004)
5. If (2, 3), (4, -3) and (4, 5) are the mid-points of the sides of a triangle, find the
coordinates of its centroid.​

Answer 1

from 1 and 2 we get Answer:

Step-by-step explanation:

2=x1+x2/2=x1+x2=4

4=x1+x3/2=x1+x3=8

4=x2+x3/2=x2+x3=8

from 1 and 2 we get x3-x2=4

from x2+x3=8 and  x3-x2=4

we get 2x3=12

x3=6

x2=2

x1=2

y1+y2/2=3=y1+y2=6

y1+y3/2=-3=y1+y3=-6

y2+y3/2=5=y2+y3=10  y2-y3=12

from equations y2+y3=10 y2-y3=12

2y2=22

y2=11

y3=-1

y1=-5

we centroid x1+x2+x3/3,y1+y2+y3/3

10/3,5/3