Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively, they add up to 92. Find these numbers

Answer 1

Let the three consecutive integers be x, x + 1 and x + 2

When, 2, 3 and 4 multiplied by x, x + 1 and x + 2, the numbers becomes 2(x), 3(x + 1) and 4(x + 2)

The three consecutive integers add upto 92

According to the question,

2(x) + 3(x + 1) + 4(x + 2) = 92

2x + 3x + 3 + 4x + 8 = 92

9x + 11 = 92

9x = 92 - 11

9x = 81

x = $\dfrac{81}{9}$

x = 9

1st integer => x

=> 9

2nd integer => x + 1

=> 9 + 1

=> 10

3rd integer => x + 2

=> 9 + 2

=> 11

$\therefore{}$ The three consecutive integers are 9, 10 and 11 respectively

Answer 2

$\textbf{\huge{ANSWER:}}$

As these numbers are consecutive, they'll be:
x , x + 1 , x + 2

According to the Question, numbers:
2x, 3 ( x + 1 ) , 4 ( x + 2 )

The sum is = 92. Therefore;

2x + 3x + 3 + 4x + 8 = 92

=》 9x + 11 = 92

=》 9x = 92 - 11

=》 9x = 81

=》 x = 9

Thus,

x = 9

x + 1 = 10

x + 2 = 11

Hope it Helps!! :)