Question

Ideal heat engine operates in carnot cycle between 227°c and 77°c. it absorbs 2 × 104 cal heat from source at high temperature. the amount of heat rejected to sink at lower temperature is

Answer 1

Hence the amount of heat rejected to sink at lower temperature is W = 1.2 K.cal

Explanation:

The efficiency of heat engine is

η = ​W  /  Q  1

η = 1 −   T  2  / T 1

Here,

• Q  1  ​= heat absorbed from the source of heat = 6 k.cal
• T  1  = temperature of source = 227 + 273 = 500 K
• T2  = temperature of sink = 127 + 273 = 400 K

Hence  

W  / 6   = 1 - 400 / 500

W / 6 = 1/5

W = 1.2 K.cal

Hence the amount of heat rejected to sink at lower temperature is W = 1.2 K.cal

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