Question

identical bulbs each having resistance R are connected with a battery of emf E and internal resistance R The raof total power consumed before and after closing key K is. please friends answer rhis question with explanation​

Answer 1

Equivalent resistance of N bulbs=

N

R

Now,current in the circuit=i=

N

R

+r

E

⟹i=

R+Nr

NE

This current gets distributed among N equal resistance bulbs connected in parallel.

Hence, current through each bulb=i

o

=

N

i

=

R+Nr

E

Power consumed by each bulbP

o

=i

o

2

R

⟹P

o

=

(R+Nr)

2

E

2

R

Hence, X=1

Answer 2

Explanation:

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Asked on November 22, 2019 by

Ribiyana Jaiwal

In an experiment, N identical electrical bulbs, each having resistance R, are connected in parallel to a dc source of emf E and internal resistance r. If the power consumed by each bulb is

(Nr+R)

2

XE

2

R

. Find out the value of X

Help best friend

Study later

ANSWER

Equivalent resistance of N bulbs=

N

R

Now,current in the circuit=i=

N

R

+r

E

⟹i=

R+Nr

NE

This current gets distributed among N equal resistance bulbs connected in parallel.

Hence, current through each bulb=i

o

=

N

i

=

R+Nr

E

Power consumed by each bulbP

o

=i

o

2

R

⟹P

o

=

(R+Nr)

2

E

2

R

Hence, X=1