Question

identify a rational number among the following numbers → √25/6 ; √20/4 ; √2 ; √3 ; 2.27(remember there's a bar upon 27)

Answer 1

Answer:

Here all are irrational number except 2.27 because their is bar upon 27

hence, it is non terminating but recurring decimal expansion

Therfore the rational number is 2.27

Answer 2

Concept: Rational numbers are those numbers which can be shown in the form of p/q, where q≠0. It is the type of real numbers.

Given: a) √25/6

b) √20/4

c) √2.√3

d) 2.27

Find: Identify which is a rational number.

Solution:

a) $\sqrt{\frac{25}{6} }$

=5/√6

=5/2.45

=2.040...

$\sqrt{\frac{25}{6} }$ is an irrational number.

b) √20/4

=√5

=2.236..

√20/4 is an irrational number.

c) √2.√3

=√6

=2.44...

=  √2.√3 is an irrational number.

d) 2.27...

= x=2.2727... →(1)

Multiply both sides by 100

100x= 227.2727... →(2)

Subtract eq. (1) from eq. (2)

99x=225

x=225/99

2.27... is a rational number because it is in the p/q form.              

Final answer: 2.27... is a rational number.

#SPJ3