Question

Identify the 31st term of an arithmetic sequence where a1 = 26 and a22 = −226.

Answer 1

Answer:

-386

Step-by-step explanation:

Here,given

a=26

a22=-226

a+21d=-226

26+21d=-226

21d=-252

d=-12

then,a31=a+30d

a31=26+30(-12)

a31=-386