Question

identify the amount of acetic acid present in 200 ml vinegar with 4 % percentage

Answer 1

Answer:

Going back to moles, you can calculate the mass of acetic acid in the solution by multiplying the moles by the molar mass of the acetic acid ( 60.05gmol ). This will then be divided by the volume of the solution in mL.

Explanation:

hope it helps you ^_^

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Answer 2

Answer:

The amount of acetic acid present in 200 mL of vinegar is $m = 10.5 g$

Explanation:

Given, the volume of vinegar = 200 ml with v/v percentage = 4%

Step(1): Here, we try to calculate the volume of the acetic acid

            $Volume (V) = 250.0mL vinegar \times\frac{4 mL acetic acid}{100mL vinegar} =10 mL acetic acid$

 Step(2): And now, we Calculate the mass of the acetic acid

         We know that density of the acetic acid is 1.05 g/mL

So, $Density(d) = \frac{mass(m)}{volume(V)}$

$Mass(m) = density(d)\times volume(V)$

$m = 1.05g/mL\times10mL$

$m = 10.5 g$

Therefore,  the amount of acetic acid present in 200 ml vinegar with 4 % v/v percentage is 10.5 g.

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