Math, asked by jaseem4728, 1 year ago

Identify the oblique asymptote of f(x) = quantity x plus 4 over quantity 3 x squared plus 5 x minus 2.

Answers

Answered by abhi178
0

Answer:


Step-by-step explanation: your question is incomplete . a complete question is ———> Identify the oblique asymptote of f(x) = quantity 3 x squared plus 2x minus 5 over quantity x minus 4.

y = 0

y = 3x − 10

y = 3x + 14

No oblique asymptote


Solve  : you should first understand what is slant or oblique asymptote ?

A slant (oblique) asymptote occurs when the polynomial in the numerator is a higher degree than the polynomial in the denominator, To find the slant asymptote you must divide the numerator by the denominator ,

e.g., f(x) = (3x² + 2x - 5)/(x - 4)

 = (3x² - 12x + 14x - 56 + 51)(/(x - 4)

= {3x(x - 4) + 14(x - 4) + 51}/(x -4)

= (3x + 14)(x - 4)/(x -4) + 51/(x - 4)

= 3x + 14 + 51/(x - 4)

At x → 4 ; f(x) → ± ∞

Hence, y = 3x + 14 is the oblique projectile


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