Identify the oxidising and reducing agent tv 3 4 4 + hcl gives rise to pbcl2 + cl2 + 4 h2o
Answers
Answered by
1
Hi there,
Pb3O4 +8HCl = 3PbCl2 + Cl2 +4H2O
■ The oxidation no of Pb in Pb3O4 = 3
■ The oxidatiom no of Pb in PbCl2 = 2
《Pb》 is reduced due to the decrease in the oxidation no, so it is the oxidizing agent
● The oxidation no of Cl in HCl is -1
● The oxidation no of Cl in Cl2 is 0
《Cl》 is oxidized due to the increase of the oxidation no, so it is the reducing agent
♡ Hope the answer is helpful
♡ Plz mark it as brainliest
Similar questions