Identify the perimeter and area of a square with diagonal length 6√3in. Give your answer in simplest radical form. HELP ASAP!!
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Answered by
17
Answer:
Step-by-step explanation:
diagonal^2= side^2+ side^2
108 = 2 side^2
side^2 = 54
side^2 = area = 54 in^2
perimeter = 4* side
4*sqrt(54) = 4*3sqrt(6)
= 12sqrt(6) in
so second option is right answer
Answered by
8
Here, we have,
Area of the square = 1/2 * (diagonal) ^2 = 1/2*(6*3^1/2) = 1/2 * 108 = 54
Again, area of the square = (side) ^2
Let the side be x.
So, x^2 = 54
Or, x = 3*6^1/2
Thus, perimeter = 4 * 3*6^1/2 = 12*6^1/2
Thus, option B is correct.
If helps, please mark it as brainliest ^_^
Area of the square = 1/2 * (diagonal) ^2 = 1/2*(6*3^1/2) = 1/2 * 108 = 54
Again, area of the square = (side) ^2
Let the side be x.
So, x^2 = 54
Or, x = 3*6^1/2
Thus, perimeter = 4 * 3*6^1/2 = 12*6^1/2
Thus, option B is correct.
If helps, please mark it as brainliest ^_^
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