Question

Identify the reducing agent in the following cases :-
(i) $4NH_{3} + 5O_{2} ----\ \textgreater \ 4NO + 6H_{2} O$
(II) $H_{2}O + F_{3} -----\ \textgreater \ HF + HOF$

Answer 1

★ 4NH₃ + 5O₂ ⇒ 4NO + 6H₂O

In the above reaction, NH₃ is getting oxidised as hydrogen is removed and oxygen is added as it becomes NO. Also, O₂ is getting reduced because hydrogen is added and it becomes H₂O.

Therefore, NH₃ is the reducing agent in the above reaction.

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★ H₂O + F₃⇒ HF + HOF

In the above reaction, F₃ is getting reduced as hydrogen is added and becomes HF. Also, H₂O is getting oxidised as one hydrogen atom is removed and it becomes HOF.

Therefore, H₂O is the reducing agent for the above mentioned reaction.