Question

. Identify the substance oxidized and reduced in the following cases .Also identify oxidising agents and reducing agent .

(i)CuO + H2 →Cu + H2 O (ii) MgCl2 +2 K → 2 KCl +Mg

(iii)Pb3 O4 + HCl → PbCl2 + Cl2 +H2 O

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Answer 1

Answer:

1. (i)Oxidised= h2(Reducing agent)

(ii)Reduced= Cu(Oxidizing agent)

2. (i)Oxidised=k(Reducing agent)

(ii)Reduced= Mg(Oxidizing agent)

3. (i)Oxidised= h2(Reducing agent)

(ii)Reduced=Pb(Oxidizing agent)

Answer 2

Answer:

Explanation:

1) copper gets reduced and hydrogen gets oxidized.

2) Magnesium gets reduced and potassium gets oxidized.

3) leads get reduced and hydrogen gets oxidized