Identify the unit vector in the following.
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A vector is said to be unit vector when magnitude of it is unity.
I mean, if A is an unit vector then, |A| = 1
Let's check which is unit vector ,
option (a) :- i + j
Magnitude = √(1² + 1²) = √2 ≠ 1
∴ i + j is not a unit vector
Option (b) :- i/√2
magnitude = 1/√2 ≠ 1
not an unit vector
option (c) :- k - j/√2
magnitude = √(1² + 1/√2²) = √3/√2 ≠ 1
not an unit vector
option (d) :- (i + j)/√2
magnitude = √(1/2 + 1/2) = 1
It is an unit vector
Hence, option (d) is correct
I mean, if A is an unit vector then, |A| = 1
Let's check which is unit vector ,
option (a) :- i + j
Magnitude = √(1² + 1²) = √2 ≠ 1
∴ i + j is not a unit vector
Option (b) :- i/√2
magnitude = 1/√2 ≠ 1
not an unit vector
option (c) :- k - j/√2
magnitude = √(1² + 1/√2²) = √3/√2 ≠ 1
not an unit vector
option (d) :- (i + j)/√2
magnitude = √(1/2 + 1/2) = 1
It is an unit vector
Hence, option (d) is correct
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