identify the unit vector in the following
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the correct answer is| i+ j|/√2
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The correct answer is option (d) (i+j)/√2.
- The magnitude of a unit vector is always equal to 1. The magnitude of a vector a+b is √(a²+b²).
- First, we will calculate the magnitude of the vector given in option 1. |i+j| = √(1+1) = √2.
- Now, for the second option |i/√2| = √(1/2) = 1/√2, for the third option |k-j/√2| = √1+1/2 = √3/2.
- Now, for the last option magnitude will be |(i+j)/√2| = √(1/2+1/2) = √1 = 1. So option d is correct as the magnitude comes out to be 1.
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