Identify which of the following rational numbers have a terminating and which of them have a non terminating decimal expansions?
A)15/1600
B)17/6
C)23/8
D)35/50
Pls answer fast!!!!!!!!!!
Answers
Question :-- Identify which of the following rational numbers have a terminating and which of them have a non terminating decimal expansions?
A)15/1600
B)17/6
C)23/8
D)35/50
Solution :-
Let See Easiest Trick For This Question :-
Answer (1) :- 15/1600
Find Prime Factors of Denominator Now.
→ 1600 = 2 * 2 * 2 * 2 * 2 * 2 * 5 * 5
Now,
Remember :- if Prime Factors of Denominator are 2 or 5 or both than the Number is a terminating Number. And if Prime Factors are other than 2 or 5 , the number is non terminating recurring..
So,
we can say That, our First Number (15/1600) is Terminating As Prime Factors of Denominator are 2 and 5 only.
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Answer (2) :- 17/6
Prime Factors of Denominator :-
→ 6 = 2 * 3
Prime Factors are other than 2 or 5. (3).
So, (17/6) is a non terminating recurring.
decimal expansion.
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Answer (3) :- (23/8)
Prime Factors of Denominator :-
→ 8 = 2 * 2 * 2
Prime Factors of Denominator are 2 only.
So, (23/8) is a terminating decimal expansion.
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Answer (4) :- (35/50)
Prime Factors of Denominator :-
→ 50 = 2 * 5 * 5
Prime Factors of Denominator are 2 & 5 both.
So, (35/50) is a terminating decimal expansion.
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The given rational numbers have terminating or non terminating decimal expansions .
( Without performing actually division )
☆ The main key point to find it out is . If the prime factors of the denominator are in the form 2^m. 5^n then the number have terminating decimal expansion . Or if they are not in this form then they have non terminating repeating decimal expansion .
1st rational number :-
⇝ 15/1600
⇝ Prime factors of 1600 are → 2 × 2 × 2 × 2 × 2 ×2 × 5 × 5
⇝ 2^6 . 5² = 2^m . 5^n
So here m = 6 and n = 2 . Hence factors are in 2^m . 5^n form . So this have terminating decimal expansion.
2nd number :-
⇝ 17/ 6
⇝ Prime factors of 6 = 2× 3 .
So it's not in the form 2^m . 5^n . So this is a non terminating repeating decimal expansion.
3rd number :-
⇝ 23/8
⇝ Prime factors of 8 = 2 × 2 × 2 × 1
Here we have only 2 . But we also have 1 as it's prime factor . So let's do a little bit change .
⇝ 5^0 = 1 . Do replacing 1 by 5^0 we'll got the required form .
⇝ 2^3 . 5^0 = 2^m . 5^n
Where m = 3 and n = 0 .
Hence this have a terminating decimal expansion.
4th number :-
⇝ 35/50 :-
⇝ Prime factors of 50 = 2 × 5× 5
⇝ 2^1 . 5^2 = 2^m . 5^n
Here also we have the required form . So this also have a terminating decimal expansion.