identities
(3x+4y) (3x-5y)
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Answered by
2
Answer:
(3x+4y)(3x+5y)
=[3x(3x+5y)]+[4y(3x+5y)]
=[3x(3x)+3x(5y)]+[4y(3x)+4y(5y)]
=(9x
2
+15xy)+(12xy+20y
2
)
=9x
2
+15xy+12xy+20y
2
=9x
2
+27xy+20y
2
Hence (3x+4y)(3x+5y)=9x
2
+27xy+20y
2
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