Math, asked by ganesh9337, 3 months ago

Verify sec^2 theta-tan^2 theta=1,for theta=0 degrees,30 degrees,45 degrees,60 degrees.​

Answers

Answered by Anonymous
7

Step-by-step explanation:

sec^2 0°-tan^2 0°=1-0=1

sec^2 30°-tan^2 30°=4/3-1/3

sec^2 45°-tan^3 45°=1

sec^2 60°-tan^2 60°=1

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