Identity (a-b)³-(a+b)³=
Answers
Answered by
16
Hi friend!!
We know that
(a+b)³=a³+b³+3a²b+3ab²
(a-b)³=a³-3a²b+3ab²-b³
Now, (a-b)³-(a+b)³
=a³-3a²b+3ab²-b³-(a³+b³+3a²b+3ab²)
=-6a²b-2b³
=-2b(3a²-b²)
I hope this will help you ;)
We know that
(a+b)³=a³+b³+3a²b+3ab²
(a-b)³=a³-3a²b+3ab²-b³
Now, (a-b)³-(a+b)³
=a³-3a²b+3ab²-b³-(a³+b³+3a²b+3ab²)
=-6a²b-2b³
=-2b(3a²-b²)
I hope this will help you ;)
Yuvrajkatiyar:
Very very thanks
Answered by
14
Hey dear!
Here is yr answer.......
= (a-b) ³ - (a+b)³
[ (a-b)³ = a³-3a²b+3ab²-b³ ]
[ (a+b)³ = a³+3a²b+3ab²+b³]
= a³-3a²b+3ab²-b³-(a³+3a²b+3ab²+b³)
= a³-3a²b+3ab²-b³-a³-3a²b-3ab²-b³
= -6a²b - 2b³
= -2b(3a²-b²) ✔
Hope it hlpz....
Here is yr answer.......
= (a-b) ³ - (a+b)³
[ (a-b)³ = a³-3a²b+3ab²-b³ ]
[ (a+b)³ = a³+3a²b+3ab²+b³]
= a³-3a²b+3ab²-b³-(a³+3a²b+3ab²+b³)
= a³-3a²b+3ab²-b³-a³-3a²b-3ab²-b³
= -6a²b - 2b³
= -2b(3a²-b²) ✔
Hope it hlpz....
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