Identity,evaluate (100+3)square
harjeet123:
(100+3)²= 100²+3²+2(100)(3)
10000+9+600= 10609 ans
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Answered by
1
(100+3)^2
(a+b)^2=a2+b2+2ab
(100)2+(3)^2+2×100×3
10000+9+600
ans is 10609
(a+b)^2=a2+b2+2ab
(100)2+(3)^2+2×100×3
10000+9+600
ans is 10609
Answered by
3
(100+3)^2=(103)^2
a = 100
b = 3
identity =a^2+2ab+b^2
100^2+2×100×3+3^2
10000+600+9
10609
ur ans
hope this is correct plz comment
a = 100
b = 3
identity =a^2+2ab+b^2
100^2+2×100×3+3^2
10000+600+9
10609
ur ans
hope this is correct plz comment
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