Identity,evaluate (100+3)square
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3
( 100 + 3)^2
= (100)^2 + (3)^2 + 2(100)(3)
[ (a+b)^2 = a^2 + b^2 + 2ab]
= 10000 + 9 + 600
= 10609
= (100)^2 + (3)^2 + 2(100)(3)
[ (a+b)^2 = a^2 + b^2 + 2ab]
= 10000 + 9 + 600
= 10609
Answered by
4
(100 + 3)²
×××××××××××××××××××
By identity,
(a + b)² = a² + b² + 2ab
×××××××××××××××××××
=> (100 + 3)²
=> (100)² + (3)² + 2(100×3)
=> 10000 + 9 + 600
=> 10609
I hope this will help you
(-:
×××××××××××××××××××
By identity,
(a + b)² = a² + b² + 2ab
×××××××××××××××××××
=> (100 + 3)²
=> (100)² + (3)² + 2(100×3)
=> 10000 + 9 + 600
=> 10609
I hope this will help you
(-:
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