Chemistry, asked by chemistry954, 1 year ago

ideofom test is given by​

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Answered by Anonymous
5
hey mate, here's your answer....

Any compound containing the CH3C=O group or the CH3CH(OH)group gives a positive result with the iodoform test. When I2 and NaOH is added to a compound containing one of these groups, a pale yellow precipitate of iodoform(triiodomethane) is formed.

The iodoform test can therefore be used to identify aldehydes and ketones; is the compound is an aldehyde then it must be ethanal (this is the only aldehyde with the CH3C=O group). This occurs as three I atoms replace the H atoms of CH3C=OR, and the C-C bond breaks due to the electron withdrawing effect of the three I atoms (as I is more electronegative than C) forming CHI3 and the salt anion of a carboxylic acid (depending on the R group of the original compound, which influences the length of the carbon chain of the anion RCOO- that is formed).

...hope this helps...

Anonymous: indications of iodoform test:-
Anonymous: The reaction of iodine and base with methyl ketones is so reliable that the "iodoform test" (the appearance of a yellow precipitate) is used to probe the presence of a methyl ketone. This is also the case when testing for specific secondary alcohols containing at least one methyl group in alpha-position.
Anonymous: ...hope I could help you...
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