Ids have the same perimeter. One is a square of side 72m and another is a rectan
h 80 m. Which field has the greater area and by how much?
Answers
Answer:
perimeter is same so
4(72)=2(80+b)
288=160+2b
64=b
area of rectangle =80+64
5120
area of squre =72*72=5184
area of squre is more is more than rectangle
by 5184-5120=64
Here, perimeter of the square field
= 4 * 72 m
= 288 m.
_ _ _ _ _ _
Now, the square field and the rectangular field, both have the same perimeter.
So, perimeter of rectangular field = 288.
Let, the breadth of the rectangular field be ' b' in metres.
So, by condition, we have,
2 ( 80 + b) = 288
=> 160 + 2b = 288
=> 2b = 288 - 160 = 128
=> b = 128/2 = 64.
So, breadth = 64m
_ _ _ _ _ _
Now, area of the square field
= side * side
= 72 * 72 sq.m
= 5184 sq.m
_ _ _ _ _ _
Area of the rectangular field
= length * breadth
= 80 * 64 sq.m
= 5120 sq.m
_ _ _ _ _ _
Hence, the square field has a greater area by (5184 - 5120) = 64 sq.m
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