Question

if 0.02g of a volatile compound on heating displaces 11.2ml of dry air at stp , the molecular weight of the compound is

Answer 1

Answer:

40

Explanation:

Given,

mass = 0.02 g

Volume = 11.2 ml = 0.0112 L

Molecular weight = x

Pressure = 1 atm

Temperature = 273 K

R= 0.0821

We know,

Pressure, volume, Universal gas constant and Temperature be denoted by P,V, R and T respectively.

PV= nRT

1 * 0.0112 = (0.02*0.0821* 273)/M

M = 40