Question

If (0.2) to the power n = 0.00032 find= n

Answer 1

Answer:

3.56

Step-by-step explanation:

${0.2}^{n} = 0.00032$

taking antilog

$n = log_{0.2}(0.00032)$

$n = \frac{ log_{10}(0.00032) }{ log_{10}(0.2) }$

$n = \frac{ - 3.49}{ - 0.98}$

$n = 3.56$

Answer 2

Answer:

${(0.2)}^{n} = 0.00032 \\ ( { \frac{2}{10} })^{n} = \frac{32}{100000} \\ ( { \frac{2}{10} })^{n} = ( { \frac{2}{10} })^{5} \\ n = 5$