Question

If (0.2)x = 2 and log 2 = 0.3010, then the value of x to the nearest tenth is:

(a) -10.0, (b) -0.5, (c) -0.4, (d) -0.2, (e) 10.0


Full explain

Answer 1

Step-by-step explanation:

(0.2)×

log(0.2)× =log 2

X log(0.2)=0.3010

log(2/10)=0.3010

X (log2-log 10)=0.3010

=0.3010

x(0.699)=0.3010

X=0.699/0.3010

X=0.4

Answer 2

Answer:

A/c to question,

(0. 2)× = 2

now multiply by log both side

log (0.2)× = log 2

x log 0.2 = log 2

x = log 2 / log 0.2

$x = \frac{log2}{log ( \frac{2}{10}) }$

$here \: using : formula</h3><p></p><p> \\ \ log ( \frac{m}{n} ) = logm \: - logn$

$x = \frac{log2}</p><p></p><p>{log( \frac{2}{10} )} = \frac{log2}{log2 - log10}$

$x = \frac{0.3010}{0.3010 - 1} = \frac{0.3010}{ - 0.699}$

x = - 0.4 answer

hope it helps