If 0.254 bar on 54 express does p by q hcf of p, q is 1 find the value of p and p + q is
Answers
Answered by
13
Answer:
Step-by-step explanation:
X = 0.254 ( bar on 54)
Multiplying by 10
10x = 2.54 ..............1
Multiplying by 100
1000x = 254.54.........2
Subtracting eq 1 frm 2
1000x - 10x = 254.54-2.54
990x = 252
X = 990/252 =485 / 126
P/q = 485/126
The Hcf of 485 and 126 is 1
P = 485 , q = 126
P+q = 485 + 126 = 611
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Answered by
0
Answer:
69
Step-by-step explanation:
0.254 (bar on 54)
x = 2.5454..
10x = 2.5454..
1000x = 254.5454...
NOW SUBTRACT (1) FROM (2)
1000x - 10x = 254.5454.. - 2.5454..
= 990x = 252
= x = 252÷ 990
= x = 14/55 ( HCF is 1)
now add 14+55 = 69
therefore, ans= 69
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