Question

If 0.2ohm, 0.3ohm, 0.4ohm. 0.5ohm and 12ohm resistors are connected in parallel to a 9v battery in parallel what will be the current through the 12 ohm resistor

Answer 1

Given :

↗ Five identical resistors of resistances 0.2Ω, 0.3Ω, 0.4Ω, 0.5Ω and 12Ω are connected in parallel.

↗ Voltage of battery = 9V

To Find :

↗ Current through the 12Ω resistor.

Concept :

❇ As per ohm's law, Current flow through a resistor is directly propoetional to the applied potential difference. (at constant temperature)

❇ Pd remains same across all resistors in parallel connection.

Calculation :

$\dashrightarrow\sf\:V=IR\\ \\ \dashrightarrow\sf\:9=I\times 12\\ \\ \dashrightarrow\sf\:I=\dfrac{9}{12}\\ \\ \dashrightarrow\underline{\boxed{\bf{\green{I=0.75A}}}}\:\orange{\bigstar}$

Answer 2

$\large{\red{ \bf{ \underline {\underline{Answer}}}}} \\ \\ \purple{ \sf{\mapsto 0.75A}} \\ \\ \mathrm{\green{ \underline{Given}}} \\ \\ \sf{ \rightsquigarrow 5 \: resitors \: in \: parallel \: with \: a \: battery \: of} \\ \sf{9 \: volt \: connected.}\\ \\ \mathrm {\blue{ \underline{ To \: Find}}} \\ \\ \sf{ \rightsquigarrow Current \: through \: 12 \Omega \: resistor = \: ? }$

$\pink{\bf{\underline{Solution:}}}$

Since all the resistors are in parallel, potential difference across them will be same and is equal to 9v

So current through the 12Ω resistor is given by

$\sf{\implies I = \frac{V}{R} } \\ \\ \sf{ \implies I=\frac{9}{12}} \\ \\ \sf{ \purple{ \implies}} \purple{ \underline{ \boxed{ \rm{I=0.75A}}}}$