Question

if 0.3 nol of hydrogen and 2mole of sulfur are takej what is tha conve of h2s at equilirium kc is 0.08​

Answer 1

Answer:

The given reaction is :

              H  

2

​  

(g)+S(s)⇌H  

2

​  

S(g)

t = 0              0.3         2              0

t = ts          0.3-x                          x

K  

c

​  

=  

[H  

2

​  

]

[H  

2

​  

S]

​  

 

By substituting the given values, we get

0.08=  

0.3−x

x

​  

 

On solving, we get

x=0.022

As we know that,  

P=  

V

nRT

​  

 

   =  

2

0.022×0.0821×360

​  

 

    =0.32 atm

The partial pressure of H  

2

​  

S is 0.32 atm.