Question

If 0.3528 is expressed in the form of given in image, find the smallest value of m, n, and P.​

Answer 1

Answer:

n=1 and m= 4

Step-by-step explanation:

If 0.3528 is expressed in the form of

$\begin{gathered} \frac{p}{ {2}^{n} \times {5}^{m} }\\ \end{gathered}$

then to find the smallest value of m and n, follow these simple steps

$\begin{gathered}0.3528 \\ \\ = \frac{3528}{10000} \\ \\ = \frac{3528}{ {10}^{4} } \\ \\ = \frac{3528}{ {(2 \times 5)}^{4} } \\ \\ = \frac{3528}{ {2}^{4} \times {5}^{4} } \\ \\ \end{gathered}$

but this time the fraction is not standard,because numerator and denominator are not coprime,so

$\begin{gathered} \frac{1764}{ {5}^{4} \times {2}^{3} } \\ \\ = \frac{882}{ {5}^{4} \times {2}^{2} } \\ \\ = \frac{441}{ {5}^{4} \times 2} \\ \\ \end{gathered}$

So, the smallest values of n and m will be 1 and 4 respectively.

Hope you understand

Answer 2

Answer:

myself sneha

i am not the real user

and real user ka naam snigdha ha