if 0.3x_0.37=0.37x_0.3,then x has the value
sarmaz:
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x= –1 satisfies the given eqⁿ,it goes like
0.3(x+1)=0.37(x+1)
don't cancel x+1 both sides. as it is a zero of eqⁿ.(x+1)(0.37–0.3)=0 hence x= –1
0.3(x+1)=0.37(x+1)
don't cancel x+1 both sides. as it is a zero of eqⁿ.(x+1)(0.37–0.3)=0 hence x= –1
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