Question

if 0.7 of barium chloride is treated with 0.4 mole of potassium sulphate no of moles of barium sulphate are formed​

Answer 1

Answer:

The reaction is BaCl

2

+K

2

SO

4

→BaSO

4

+2KCl.

One mole of barium chloride reacts with one mole of potassium sulphate to form one mole of barium sulphate and two moles of potassium chloride.

Here, potassium sulphate is the limiting reagent. Hence, 0.4 mol of potassium sulphate will react with 0.4 mol of barium chloride to form 0.4 mol of barium sulphate and 0.8 mol of potassium chloride respectively.

Hence, option B is correct.