Question

maths 1÷1×2×3+1÷2×3×4+1÷3×4×5+14×5×6

\begin{gathered}1 \div 1 \times 2\times 3+1 \div2 \times3 \times4 + 1 \div3\times 4 \times 5+ 14\times 5 \times 6\\\\= \dfrac{1}{1} \times 6+\dfrac{1}{2} \times 12+ \dfrac{1}{3} \times 20 + 420\\\\=6+6+\dfrac{20}{3} +420\\\\=432+\dfrac{20}{3}\\\\=\dfrac{1296+20}{3} \\\\=\dfrac{1316}{3}\end{gathered}
1÷1×2×3+1÷2×3×4+1÷3×4×5+14×5×6
=
1
1
​
×6+
2
1
​
×12+
3
1
​
×20+420
=6+6+
3
20
​
+420
=432+
3
20
​

=
3
1296+20
​

=
3
1316
​ \dfrac{1316}{3}
3
1316
​ ​

Answer 1

Answer:

42 is the ans or u can solve ur self