Question

if 0.98g of H2SO4 are present in 500 ml solution. Find normality.​

Answer 1

Answer:

This is your answer of this question

Answer 2

Answer::

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(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)

Given:

$\bigstar$ W(weight)=0.98g

$\spadesuit$ $\bf{molecular mass of hydrogen sulphate =98}$

$\bf{Volume=500ml}$

Formula of normality ::

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$\huge\mathfrak{\underline{\underline{\red{Answer:-}}}}$

☞$\sf{Normality= \dfrac{w\times1000}{M \times V}}$

☞$\sf{Normality(N)=\dfrac{0.98\times1000}{98\times 500}}$

☞$\sf{Normality(N)=\dfrac{0.1\times1000}{500}}$

☞$\sf{Normality(N)=0.1\times2}$

☞$\sf{Normality(N)=0.2N}$

$\longrightarrow$Answer =0.2Normality