Question

if '0' and '1' are the zeroes of 2x^3-6x^2+ax+b find a and b​

Answer 1

Answer:

a = 4 and b = 0

Step-by-step explanation:

Given,

0 and 1 are zeroes of 2x³ - 6x² + ax + b

So,

x = 0 or x = 1

Let,

p(x) = 2x³ - 6x³ + ax + b

Now,

If we take p(0) and p(1) we will get 0, because 0 and 1 are factors of p(x)

Now,

x = 0

p(0) = 2(0)³ - 6(0)² + a(0) + b

0 = 2(0) - 6(0) + a(0) + b

0 = 0 - 0 + 0 + b

∴ b = 0 ----- 1

Now,

x = 1

p(1) = 2(1)³ - 6(1)² + a(1) + b

0 = 2(1) - 6(1) + a + b

0 = 2 - 6 + a + b

a + b - 4 = 0

a = 4 - b

From eq.1 we get,

a = 4 - 0

a = 4

Thus,

a = 4 and b = 0

Hope it helped and believing you understood it........All the best