If 0 is an acute angle and tan 0 =5/18
find the value of sec 0 + cosec O.
Answers
Answered by
5
Answer:
Given tan θ = 8/15
θ is an acute angle
in the figure triangle OMP is a right angled triangle,
∠M=90
0
and ∠Q=θ
tanθ=PM/OL=8/15
Therefore, PM = 8, OM = 15
But OP
2
=OM
2
+PM
2
using Pythagoras theorem,
=15
2
+8
2
= 225 + 64
= 289
=17
2
Therefore, OP = 17
secθ=OP/OM
= 17/15
cosecθ=OP/PM
= 17/8
Now,
secθ+cosecθ = (17/15) + (17/8)
= (136 + 255)/ 120
= 391/120
Step-by-step explanation:
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Answered by
0
Answer:
18/5 is the answer of sec0 + cot0
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