Question

if the arithmetic sequence of first term 8 common different 6 then what is the 10 th term?​

Answer 1

Answer:

Answer

First term of the sequence is 10 and common difference is 3.

a

1

= 10 and d = 3

Next term = a

2

=a

1

+d=10+3=13

a

3

=a

2

+d=13+3=16

Thus, first three terms of the sequence are 10, 13 and 16.

Let 100 be the nth term of the sequence.

a

n

=a

1

+(n−1)d

100=10+(n−1)3

90=(n−1)3

n−1=30

n=31, which is a whole number.

Therefore, 100 is the 31

st

term of the sequence.

Step-by-step explanation:

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Answer 2

Answer:

62

Step-by-step explanation:

first term=8

common difference=6

then,

10th term = first term +(10-1)*common difference

=8+9*6=62