Math, asked by bazicneeds, 9 months ago

If 0<θ<25, prove that cos(65+ θ) - sin(25-θ) = 0

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Answered by 217him217

16

Step-by-step explanation:

= cos(65+@)-sin(25-@)

= cos(90-25+@) - sin(25-@)

= cos(90-(25-@)) - sin(25-@)

= sin(25-@) - sin(25-@)

= 0

Answered by nani200354

2

Cos( 65+teta) - cos ( 90-25+teta)

Cos (65+teta) - cos ( 65+teta)

Which equals to 0

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