solve 2x-3/4 >= 1/2 ,x belongs to {1,2,....,8}
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Chapter 4 Linear Inequations.
M.L. Aggarwal. Class 10th.
Answers
Step-by-step explanation:
Given:-
(2x-3)/4≥1/2 ,x belongs to 1,2,..,8
To find:-
Solve (2x-3)/4≥1/2 ,x belongs to 1,2,..,8
Solution:-
Given in-equation is (2x-3)/4≥1/2
On multiplying with 4 on both sides
=>(2x-3)×4/4≥(1/2)×4
=>2x-3≥2
On adding 3 on both sides
=>2x-3+3≥2+3
=>2x+0≥5
=>2x≥5
on dividing by 2 on both sides then
=>2x/2≥5/2
=>x≥5/2 or 2.5
The value of x is greater than or equal to 5/2 or 2.5
If x belongs to natural numbers then
x=3,4,...
But given that x belongs to 1,2,...,8
according to the given condition
x=3,4,5,6,7,8
Answer:-
The solution set of x={3,4,5,6,7,8}
Check:-
1)If x=3 then (2x-3)/4
LHS=[2(3)-3]/4
=(6-3)/4
=2/4
=1/2
LHS=RHS
2)If x=4 then(2x-3)/4
LHS=[2(4)-3]/4
=(8-3)/4
=5/4
≥1/2
LHS=RHS
3)If x=5 then (2x-3)/4
LHS=[2(5)-3)]/4
=(10-3)/4
=7/4
≥1/2
LHS=RHS
4)If x=6 then (2x-3)/4
LHS=[2(6)-3]/4
=(12-3)/4
=9/4
≥1/2
LHS=RHS
5)If x=7 then (2x-3)/4
LHS=[2(7)-3]/4
=(14-3)/4
=11/4
≥1/2
LHS=RHS
6)If x=8 then (2x-3)/4
LHS=[2(8)-3]/4
=(16-3)/4
=13/4
≥1/2
LHS =RHS
Given in-equation is true for the solution set x={3,4,5,6,7,8}
Verified
Answer:
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