If 0<x<(π/4) and cosx+sinx=5/4, find the numerical values of cosx-sinx.
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cosx + sinx =5/4
square on both side
1+ 2cosxsinx=25/16
2cosxsinx=9/16
(cosx-sinx)^2+4cosxsinx=25/16
cosx-sinx=root25/16-18/16
cosx-sinx=root7/4
square on both side
1+ 2cosxsinx=25/16
2cosxsinx=9/16
(cosx-sinx)^2+4cosxsinx=25/16
cosx-sinx=root25/16-18/16
cosx-sinx=root7/4
karn89:
plz mark me as brainlist
Sure.. but can you please explain the steps after 2cosxsinx=9/16
ill just evaluate (cosx+sinx)^2 to( cosx-sinx) ^2+4sinxcosx
Ohkk
thanks
open thebracket ull get the result
Ya
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