if (1,1) is the solution of the equation px + qy + (a-b) = 0 and px + qy + (b-c) = 0 then find a+c
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Given : (1,1) is the solution of the equation px+qy+(a-b)=0 and px+qy+(b-c)=0
To Find : a+c
Solution:
px+qy+(a-b)=0
(1,1) is the solution
=> p + q + (a - b) = 0
px+qy+(b-c)=0
(1,1) is the solution
=> p + q + ( b - c) = 0
Equating both
p + q + (a - b) = p + q + ( b - c)
=> a - b = b - c
=> a + c = 2b
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