Question

if [[1 -1 x][1 x 1][ x -1 1]] has no inverse then the real value of x is (pls with solutions pls)​

Answer 1

Answer:

x=0

Step-by-step explanation:

([1-1x)(1x1)(x-11)

[0(1)(x-11)]

[0(x-11)]

[x-0]

x=0

Hope it helps!

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