Math, asked by khwaiskhhh, 9 months ago

if (1^2+2^2+3^2+..... 12^2) =650, then the value of (2^2+4^2+6^2+.... 24^2) is​

Answers

Answered by chandradeep2911
11

Answer:

2600

Step-by-step explanation:

here,

2^2 + 4^2 + 6^2 +..... +24^2 can be written as :--

2^2 ( 1^2 + 2^2 + 3^2 +....+12^2)

= 4 * 650

= 2600

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