if 1^2 + 2^2 ...... 512^2 = m,then 2^2 +4^2 +6^2 ......+1024^2
Anonymous:
4m
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Answered by
7
2^2 + 4^2 + 6^2 ......+ 1024^2 =
4×(1^2 + 2^2 + 3^2 ......+ 512^2) =
4m
4×(1^2 + 2^2 + 3^2 ......+ 512^2) =
4m
Answered by
9
1² + 2² ...... 512²= m
So, 2²+4²+6²+.....+1024²
=2²(1² + 2²+3²+ ...... 512²)
=4m
So, 2²+4²+6²+.....+1024²
=2²(1² + 2²+3²+ ...... 512²)
=4m
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