if 1,2,3 and 4 are the roots of equation x4+ax3+bx2+cx+d=0 then a+2b+c=?
Answers
Answered by
0
Answer:
10
Step-by-step explanation:
the given roots are 1,2,3,4
(x-1)(x-2)(x-3)(x-4)=0 {acc. to the formula of equation when the roots given}
(x2-3x+2)(x2-7x+12)=0
x4-10x3+35x2-50x+24=0
Thi represents the given equation, x4+ax3bx2cx+d=0
we get a= -10, b= 35, c= -50, d= 24
we need a+2b+c= -10+2(35)-50
= -10+70-50
=10
Similar questions