Math, asked by rahman2066, 9 months ago

if 1,2,3 and 4 are the roots of equation x4+ax3+bx2+cx+d=0 then a+2b+c=?​

Answers

Answered by pavanasrigayathri
0

Answer:

10

Step-by-step explanation:

the given roots are 1,2,3,4

(x-1)(x-2)(x-3)(x-4)=0        {acc. to the formula of equation when the roots given}

(x2-3x+2)(x2-7x+12)=0

x4-10x3+35x2-50x+24=0

Thi represents the given equation, x4+ax3bx2cx+d=0

we get a= -10, b= 35, c= -50, d= 24

we need a+2b+c= -10+2(35)-50

                             = -10+70-50

                           =10

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