Question

If 1+2+3+....+n=120,find 1^3+2^3+....+n^3​

Answer 1

Answer:

14400

Step-by-step explanation:

n(n+1)/2 = 120

sumof cube for n terms = [n(n+1)/2]² = 120² = 14400

Answer 2

Answer:

14,400

Step-by-step explanation:

n(n+1)/2=120

&1^3+...+n^3={n(n+1)/2}^2

i.e.120×120=14,400

i hope it will help uh!