Question

if (1,2) (4,3) (6,4) are the midpoints of sides BC,CA,AB of trianlge ABC then the equation of AB is​

Answer 1

Answer:

x-3y+6=0

Step-by-step explanation:

From the figure, we can see that EF is parallel to BA. EF line equation is

$y - 3 = \frac{3 - 2}{4 - 1} (x - 4) \\ y - 3 = \frac{1}{3} (x - 4) \\ 3y - 9 = x - 4 \\ x - 3y + 5 = 0$

Now, equation of line parallel to this line is x-3y+k=0. This line passes through the point D(6,4). The equation becomes

$x - 3y + k = 0 \\ 6 - 12 + k = 0 \\ k = 6$

Hence, the equation of line AB is x-3y+6=0.

Thank you

Answer 2

Step-by-step explanation:

equation of AB is

• x1+x2=12--------equation(1)
• y1+y2=8---------- equation(2)

I hope it helps you

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