If 1, ω, ω² are the cube roots of unity, then the value of [1/(1+ω) + 1/(1+ω²)] is
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Step-by-step explanation:
Given 1,ω,ω² are cube roots of unity
therefore ω = -1/2+i√3/2
ω² = -1/2 - i√3/2
1+ω+ω²=0 && 1/ω=ω²
From the above formulaes
1/(1+ω) ------>>>1/-ω²--->> -ω
1/(1+ω²)----->>>1/-ω ---->> -ω²
-ω-ω²=1
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