Math, asked by tusharrain3515, 4 months ago

If 1, ω, ω² are the cube roots of unity, then the value of [1/(1+ω) + 1/(1+ω²)] is

Answers

Answered by mamidalahemanthreddy
0

Answer:

1

Step-by-step explanation:

Given 1,ω,ω² are cube roots of unity

therefore ω = -1/2+i√3/2

ω² = -1/2 - i√3/2

1+ω+ω²=0 && 1/ω=ω²

From the above formulaes

1/(1+ω) ------>>>1/-ω²--->> -ω

1/(1+ω²)----->>>1/-ω ---->> -ω²

-ω-ω²=1

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